(3/16)=(1/(2x)^2)

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Solution for (3/16)=(1/(2x)^2) equation: 


D( x )

(2*x)^2 = 0

(2*x)^2 = 0

(2*x)^2 = 0

4*x^2 = 0 // : 4

x^2 = 0

x = 0

x in (-oo:0) U (0:+oo)

3/16 = 1/((2*x)^2) // - 1/((2*x)^2)

3/16-(1/((2*x)^2)) = 0

3/16-(2*x)^-2 = 0

-1/4*x^-2 = -3/16 // : -1/4

x^-2 = 3/4

-2 < 0

1/(x^2) = 3/4 // * x^2

1 = 3/4*x^2 // : 3/4

4/3 = x^2

x^2 = 4/3 // ^ 1/2

abs(x) = (4/3)^(1/2)

x = (4/3)^(1/2) or x = -(4/3)^(1/2)

x in { (4/3)^(1/2), -(4/3)^(1/2) }

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